معادلات السرعة والمسافة والزمن والمد والانجراف التي يحتاجها كل ملاح، مع أمثلة محلولة. (بالإنجليزية فقط حالياً)
Lighthouse Formula
D = 2.08 × (√H + √h)
مثال محلول
A lighthouse is charted at 80 m. Your height of eye is 9 m. At what range will the light first appear (rise)?
√80 = 8.94, √9 = 3.00 Sum = 11.94 D = 2.08 × 11.94
≈ 24.8 nautical miles
The instant a light 'rises' (first seen) or 'dips' (disappears) gives an instant position line — clock the bearing at the same moment.
Distance Off by Vertical Sextant Angle
D = 1.854 × H ÷ θ
مثال محلول
A lighthouse 120 m high subtends a vertical sextant angle of 30′. How far off are you?
D = 1.854 × 120 ÷ 30 D = 222.5 ÷ 30
≈ 7.4 nautical miles
Measure the height from the object's charted elevation. If its base is at sea level, correct for the height of tide.
Vertical Danger Angle (limiting line)
VDA = 1.854 × H ÷ d (minutes of arc)
مثال محلول
A 120 m light marks a shoal. You must stay at least 5 nm clear. What is the danger angle?
VDA = 1.854 × 120 ÷ 5 VDA = 222.5 ÷ 5
44.5′ — keep your VSA SMALLER than this to stay clear
If your measured vertical sextant angle grows larger than the VDA, you have crossed inside the limiting danger line — alter away.
Doubling the Angle on the Bow
Distance off = Distance run (when bow angle doubles)
مثال محلول
An object bears 30° on the bow (A = 30°). When it bears 60° on the bow (2A = 60°), you have run 5.2 nm. What is your distance off?
First bearing 30°, second bearing 60° = 2 × 30° ✓ Triangle is isosceles → run leg = distance-off leg
Distance off = 5.2 nm
Works for any starting angle A provided the second bearing equals exactly 2A. Common exam pairs: 30°/60°, 22½°/45°, 26½°/45°. The object is still forward of the beam when the second bearing is taken, giving time to act. See also: Four-Point Bearing (45°/90°) — the most frequently examined special case.
Four-Point Bearing (45° Rule)
Distance off (abeam) = Distance run (from 45° to beam)
مثال محلول
A headland bears 45° on the bow. When it comes abeam, you have run 3.8 nm. What is your passing distance?
45° doubles to 90° — special case of doubling the angle ✓ Distance run = 3.8 nm
Distance off = 3.8 nm
'Four points' is the old compass term for 4 × 11.25° = 45°. This is the most-examined form of the doubling-angle rule. Useful at night to gauge clearance off headlands without a sextant — note the bearing when 45° on the bow, read the log when the object comes abeam.
Safety (Anchor) Swing Circle
R = LOA + cable veered + safety margin
مثال محلول
LOA 180 m, you veer 6 shackles (the maximum), and you want a 50 m safety margin. (1 shackle = 27.5 m)
Cable = 6 × 27.5 = 165 m R = 180 + 165 + 50
R = 395 m — no charted danger may lie inside this circle
Plot the circle centred on the anchor position. If any danger falls inside it, choose a different berth, less scope, or accept a larger margin.
Bridge Swing Circle
R = (stem → standard) + cable paid out
مثال محلول
The standard compass is 140 m abaft the stem and you veer 5 shackles. What radius do you monitor on the chart? (1 shackle = 27.5 m)
Cable = 5 × 27.5 = 137.5 m R = 140 + 137.5
R = 277.5 m — the bridge (GPS) fix should always stay within this circle
Because the GPS antenna is by the bridge, this circle lets you confirm at a glance that the vessel has not dragged.
Stern Swing Circle
R = waterline length + cable paid out
مثال محلول
Waterline length 170 m; cable veered 5 shackles (137.5 m). What radius does the stern sweep?
R = 170 + 137.5
R = 307.5 m — the stern must stay clear of dangers and other ships within this circle
Use this when berths are tight or you anchor near other vessels — the stern sweeps the largest arc as the ship swings.
LDL Anchor (no squat)
LDL = Draught + Safety margin − Height of tide
مثال محلول
Draught 9.5 m, UKC margin 1.0 m, height of tide 2.3 m. What charted depth do you need at anchor?
LDL = 9.5 + 1.0 − 2.3
LDL = 8.2 m — pick a berth charted at least this deep
No squat term — the ship is stopped at anchor. Check the depth against the LOWEST height of tide expected during the stay.
Speed · Time · Distance
D = S × T (6-min rule: D = S ÷ 10)
مثال محلول
How far do you run in 6 minutes at 12 knots?
6 min = 0.1 h, so D = 12 × 0.1 Or the 6-min rule: D = S ÷ 10 = 12 ÷ 10
1.2 nautical miles
In 6 minutes (1/10 of an hour) a vessel runs one-tenth of its speed in nautical miles — handy for quick pilotage checks.
1-in-60 Rule (track error)
Error (°) = (off-track distance ÷ distance run) × 60
مثال محلول
After 10 nm you find you are 0.5 nm off track. What correction returns you to the planned track over the next 10 nm?
Track error = (0.5 ÷ 10) × 60 = 3° Double it to regain track in the same distance: 3° + 3°
6° toward the track (3° cancels the error, 3° more closes it)
A 1 nm error over 60 nm equals 1°. The rule scales for any leg length and is the basis of quick visual position-keeping.
Rate of Turn for a Radius
ROT (°/min) = 0.955 × S ÷ R
مثال محلول
You want a turn radius of 0.5 nm at 12 knots. What rate of turn do you order?
ROT = 0.955 × 12 ÷ 0.5 ROT = 11.46 ÷ 0.5
≈ 22.9 °/min
Set this on the rate-of-turn indicator to hold a planned curved track through a channel bend.
Squat — Quick Estimates
Squat ≈ V² ÷ 100 • 0.3 m per 5 kn • 10% of draught
مثال محلول
A ship drawing 10 m is making 15 knots. Estimate the squat three ways.
V² ÷ 100 = 15² ÷ 100 = 225 ÷ 100 = 2.25 m 0.3 m per 5 kn = (15 ÷ 5) × 0.3 = 3 × 0.3 = 0.9 m 10% of draught = 0.10 × 10 = 1.0 m
≈ 0.9–2.25 m — take the largest as a safe allowance and add it to draught for UKC
These are quick rule-of-thumb checks. Squat rises with the SQUARE of speed, so slowing down is the most effective way to cut it. Barrass formula: Squat ≈ Cb × V² ÷ 100 (use ÷ 50 in confined / shallow water).
Cable to Veer — Forged Steel & Aluminium Bronze
Forged steel: 1.5√d (m) or 2√d (fm) Aluminium bronze: √d (m) or 1.3√d (fm)
مثال محلول
You are anchoring in 36 m of water. How many shackles for forged-steel cable, and for aluminium-bronze cable?
Forged steel = 1.5 × √36 = 1.5 × 6 = 9 Aluminium bronze = √36 = 6
≈ 9 shackles (forged steel) or ≈ 6 shackles (aluminium bronze)
Use the factor that matches your cable's material and your depth units (metres or fathoms). Increase scope for strong wind, tide or poor holding ground.
Echo Sounder — Acoustic Depth Formula
D = (V × T) ÷ 2 · Shortcut: D = 750 × T
مثال محلول
The echo returns 0.08 s after transmission. Using the standard sound speed of 1,500 m/s, find the depth.
D = (1,500 × 0.08) ÷ 2 D = 120 ÷ 2 — or using the shortcut — D = 750 × 0.08
D = 60 m
The standard exam speed is 1,500 m/s. If the question gives a different value (e.g. 1,520 m/s in warm, saline water), substitute it and still divide by 2. The shortcut 750 × T only works when V = 1,500 m/s. Add the transducer depth to get the true water depth from the surface (see the 'Echo Sounder — True Depth & UKC' formula).
Echo Sounder — True Depth & UKC
True depth = ES reading + transducer depth UKC = ES reading − (Draught − transducer depth)
مثال محلول
The echo sounder reads 11.0 m. The transducer is 1.5 m below the waterline. The ship's draught is 9.5 m. Find the true depth and UKC.
True depth = 11.0 + 1.5 = 12.5 m UKC = 12.5 − 9.5 Or directly: UKC = 11.0 − (9.5 − 1.5) = 11.0 − 8.0
True depth = 12.5 m · UKC = 3.0 m
The echo sounder measures from the transducer downwards, not from the sea surface. Always add the transducer depth to convert the reading to true depth. Subtract the ship's draught from true depth to get UKC — or use the shortcut UKC = ES reading − (Draught − transducer depth). In pilotage, add squat to the draught before computing UKC.
LDL Pilotage (with squat)
LDL = Draught + Squat + Safety margin − Height of tide
مثال محلول
Draught 9.5 m, squat 0.8 m, UKC margin 1.0 m, height of tide 2.3 m. What charted depth must you have?
LDL = 9.5 + 0.8 + 1.0 − 2.3
LDL = 9.0 m — do not pass over any charted sounding less than this
Underway you carry squat, so it is included (unlike at anchor). The height of tide is subtracted because it adds water above the charted sounding.
Rule of Twelfths — Tidal Height
Hours 1–6: ¹⁄₁₂ · ²⁄₁₂ · ³⁄₁₂ · ³⁄₁₂ · ²⁄₁₂ · ¹⁄₁₂ of the range
مثال محلول
LW height 0.5 m, HW height 5.3 m. Estimate the height of tide 3 hours after LW.
Range = 5.3 − 0.5 = 4.8 m Hour 1: ¹⁄₁₂ × 4.8 = 0.4 m Hour 2: ²⁄₁₂ × 4.8 = 0.8 m Hour 3: ³⁄₁₂ × 4.8 = 1.2 m Total rise after 3 hours = 0.4 + 0.8 + 1.2 = 2.4 m
Height = 0.5 + 2.4 = 2.9 m above chart datum
Quick check: after 3 hours (midway) the tide has covered exactly half its range (1+2+3 = 6 twelfths). The rule assumes a smooth sinusoidal curve — it is not reliable for ports with double HWs, tidal bores, or strong shallow-water effects. For accurate work, always use the published tidal curve.
Compass Error — CADET Mnemonic
C + Dev(E) = M · M + Var(E) = T Error = True − Compass (E is +, W is −)
مثال محلول
Compass bearing 085°. Deviation 3°E. Variation 5°W. Find the true bearing.
Magnetic = 085° + 3° (Dev E, add) Magnetic = 088° True = 088° − 5° (Var W, subtract)
True bearing = 083°T · Total error = 083° − 085° = −2° (2°W)
CADET going Compass → True: add East values, subtract West. To reverse True → Compass (TVMDC): subtract East values, add West. Total compass error = True − Compass; named East if True is greater, West if True is less.
True to Compass — TVMDC / CDMVT
T − Var(E) = M · M − Dev(E) = C (CDMVT read right-to-left; E is −, W is +)
مثال محلول
You need to steer 083°T. Variation 5°W. Deviation 3°E. What compass course do you order?
Magnetic = 083° + 5° (Var W, add) = 088° Compass = 088° − 3° (Dev E, subtract) = 085°
Order 085° on the compass
Reverse of CADET: to go True → Compass, subtract East values and add West. TVMDC = 'True Virgins Make Dull Companions'. CDMVT is the same sequence read right-to-left. Cross-check with CADET: 085°C + 3°E Dev + (−5°W Var) → 083°T ✓.
Course Made Good (CMG)
CMG = the bearing of the straight line drawn from FIX to EP
مثال محلول
You steer 090° at 6 kn for 1 hour. Current sets 180° (south) at 3.5 kn. Find EP and state CMG. (Shown in the diagram above.)
1. Plot DR: from FIX go 6 nm due east (090° × 6 kn × 1 hr). 2. Apply current: from DR go 3.5 nm south (180° × 3.5 kn × 1 hr) → this is your EP. 3. Draw a straight line from FIX to EP. EP is 6 nm east and 3.5 nm south of FIX. 4. Lay a parallel ruler on that FIX→EP line and walk it to the compass rose — read off the bearing. The angle south of east = arctan(3.5 ÷ 6) ≈ 30°, so CMG ≈ 090° + 30° = 120° T.
CMG ≈ 120° T (you steered 090° but the southerly current pushed you 30° off track)
What is arctan / atan2? It is the calculator function that works backwards from a right-angle triangle — if the east leg is 6 nm and the south leg is 3.5 nm, arctan(3.5 ÷ 6) gives the angle between them (≈ 30°). On the chart you never need to calculate it: just draw the FIX→EP line and measure the bearing with parallel rulers or a plotter. The diagram above shows the three-vector triangle: Course Steered (FIX→DR) + Current (DR→EP) = Course Made Good (FIX→EP).
Speed Made Good (SMG)
SMG = distance FIX→EP ÷ elapsed time
مثال محلول
Same scenario as CMG: steered 090° at 6 kn, current 180° at 3.5 kn, for 1 hour. EP is 6 nm east and 3.5 nm south of FIX. What is SMG?
The FIX→EP line is the hypotenuse of a right triangle (east leg = 6 nm, south leg = 3.5 nm): D = √(east² + south²) = √(6² + 3.5²) = √(36 + 12.25) = √48.25 ≈ 6.95 nm SMG = 6.95 nm ÷ 1 hr
SMG ≈ 6.9 kn (faster than your 6 kn through-water speed because the current's sideways push made the FIX→EP diagonal longer than 6 nm)
On the chart: measure the FIX→EP line with dividers against the latitude scale — no maths needed. Use SMG (not engine speed) for ETAs, and CMG (not course steered) to check you're on track.
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